0=-16x^2+103x+70

Solution for 0=-16x^2+103x+70 equation:

0=-16x^2+103x+70

We move all terms to the left:

0-(-16x^2+103x+70)=0

We add all the numbers together, and all the variables

-(-16x^2+103x+70)=0

We get rid of parentheses

16x^2-103x-70=0

a = 16; b = -103; c = -70;
Δ = b2-4ac
Δ = -1032-4·16·(-70)
Δ = 15089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-103)-\sqrt{15089}}{2*16}=\frac{103-\sqrt{15089}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-103)+\sqrt{15089}}{2*16}=\frac{103+\sqrt{15089}}{32}
$